Apr 16, 2016 · You should end up with a new gaussian : take the Fourier tranform of the convolution to get the product of two new gaussians (as the Fourier transform of a gaussian is still a gaussian), then …

Oct 13, 2018 · You could do it using the Laplace transform and the convolution theorem for Laplace transforms. The Laplace transform of a Dirac delta is $$\mathcal {L} (\delta (t-a)) = e^ {-as}$$ and the …

Since the Fourier Transform of the product of two functions is the same as the convolution of their Fourier Transforms, and the Fourier Transform is an isometry on $L^2$, all we need find is an $L^2$ …

May 21, 2013 · Remark 2: I don't know a expliclty characterization of the support of the convolution, but by the given formula, you can see that if the two functions has compact support, then does the …

Feb 21, 2015 · Calculate the convolution of the product of two identical sine functions. (5.6-7) Ask Question Asked 10 years, 9 months ago Modified 1 year, 3 months ago

Jan 7, 2018 · This sort of matches my (hopefully correct) intuition. Firstly, we notice that we got out a continuous function, so convolution is smoothing things. Secondly, we took in two piecewise constant …

Derivative of convolution Ask Question Asked 13 years, 4 months ago Modified 1 year, 5 months ago

Convolution of two Schwartz functions is Schwartz Ask Question Asked 7 years, 7 months ago Modified 7 years, 7 months ago

Dec 12, 2019 · Convolution of two identical functions Ask Question Asked 5 years, 11 months ago Modified 7 months ago

The convolution of two continuous functions is continuous [duplicate] Ask Question Asked 8 years ago Modified 8 years ago